The First Variation of Energy equation can be used for image denoising. I recently wrote an article that used a variation of that equation to focus on removing “salt and pepper” style image noise. This article looks at how to defeat “gaussian” distribution noise in a color image.

Fundamentally, we’re going to do something very similar to what we did for anisotropic filtering and salt and pepper denoising. Gaussian noise differs from salt and pepper noise in that it changes pixel values from 0-255 rather than setting them to either 0 or 255. As a result, our other filter will not work.
In this case, we’re going to take the First Variation of Energy equation and change it around a little bit to find the minimum energy instead of the maximum energy of a system. What does that do? Well, consider a contour map of a mountain with a bunch of sharp spikes everywhere. That has a lot of energy. If we smoothed it and got rid of the sharp spikes, it would have less energy. By taking the Heat equation for a 2d plane, applying Neumann boundary conditions, solving the partial differential equation, then taking the inverse of the result, we’ll have an equation that gives us a stepped reduction in energy. If we take the original image, weight it by a fidelity factor, then shove that all into MATLAB, we get the below code.
We’ll then run the image, pixel-by-pixel, through our MATLAB function while taking the minimum energy each time. Again, recall that the original image is weighted by our lambda constant to ensure that we maintain image fidelity.
Each iteration of the TV Energy equation will smooth out the image. This will provide despeckling but also reduce image detail around sharp corners. We’re basically trying to round off every sharp corner in the image which removes individual noise speckles.
I took the featured image from the top of this article, applied Gaussian noise across all 3 color channels, then put it on the above left hand image. I then ran that image through the TVEnergy function shown below. Inputting random values for lambda, I got the above image after some experimentation. With a lambda of around 0.01, I got a pretty high Signal to Noise ratio for this image when compared to the original. Each image, naturally, will have its own best lambda value to get a clean result.
A = imread(‘yourimagehere.jpg’); % Load the image with this command at the command line
for i=1:3; C(:,:,i) = TVEnergy(A(:,:,i),0.01); end; % Call the function with this line, substituting your own lambda value as appropriate
function [u] = TVEnergy(f, lambda)
% Calculate TV energy value of an image.
% Author: Tyler Hardy
% www.wirebiters.com
% Input: Color image f
% Output: TV Energy of image fset(gcf,’color’,’white’); % white background
f = double(f);
dt = 0.1;
T = 20;
u = f; % u will be modified. f will not be modified and will be used for image fidelityfor t = 0:dt:T % for loop **************
[m,n] = size(f);% First center discrete derivatives
f_x = ( u(:,[2:n,n]) – u(:,[1,1:n-1]) ) / 2;
f_y = ( u([2:m,m],:) – u([1:m-1,1],:) ) / 2;% Second derivative in x: f_xx
f_xx = u(:,[2:n,n]) – 2*u + u(:,[1,1:n-1]);
% Second derivative in y: f_yy
f_yy = u([2:m,m],:) – 2*u + u([1,1:m-1],:);% Diagonal derivative f_xy
f_xy = (u([2:m,m],[2:n,n]) + u([1,1:m-1],[1,1:n-1])- u([1,1:m-1],[2:n,n])- u([2:m,m],[1,1:n-1])) / 4;% Total Variation equation
u = u + dt.*((f_xx.*f_y.^2 – 2*f_x.*f_y.*f_xy + f_yy.*f_x.^2)./((f_x.^2 +f_y.^2).^(3/2)+0.1) – 2*lambda.*(u-f));% Display the image
imshow(uint8(u)); title(t);
drawnow;end % end for *************************
end % end function
If you want to use this code, please credit it per Creative Commons to this website. Images are Public Domain from NASA.
HI !! Tyler
i can’t compile your code. it show me thatFunction definitions are not permitted in this context. and i search for fix it but it ihe same way before.what should i do
thank you
for this part:
A = imread(‘yourimagehere.jpg’); % Load the image with this command at the command line
You might have to delete the single quotes around yourimagehere.jpg and retype it by hand because the ‘ symbol doesn’t always translate over from the webbrowser to MATLAB.
You might also have to go into the function and retype the ‘ symbol and – symbol. I just tried copy+pasting the code in Chrome and it looks like Chrome is inserting a different character for – and ‘ … I’ll upload a working .m file and edit the article to reflect this.
thank you for your ans Tyler
I have one more Question. In your code can I split function in another script .m file right?? and I can use for gray scale image not only RBG image??
Yeah.
The example code is for a 3 layer (color) image. You can modify the starting code for a single layer (black and white) image.